1 answer

1 out of 3 atten Be sure to answer all parts. Ammonia is produced by the...

Question:

1 out of 3 atten Be sure to answer all parts. Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation N2(g) + 3H2(g) → 2NH3(g) Calculate the mass of ammonia produced when 35.0 g of nitrogen react with 15.3 g of hydrogen. NH3 Which is the excess reactant and how much of it will be left over when the reaction is complete? hydrogern nitrogen SAMSUN 2 3 4 5 6
1 out of 3 atten Be sure to answer all parts. Ammonia is produced by the reaction of nitrogen and hydrogen according to the equation N2(g) + 3H2(g) → 2NH3(g) Calculate the mass of ammonia produced when 35.0 g of nitrogen react with 15.3 g of hydrogen. NH3 Which is the excess reactant and how much of it will be left over when the reaction is complete? hydrogern nitrogen SAMSUN 2 3 4 5 6

Answers

35.0 g of N2 = 35.0 / 28.01 = 1.25 moles

15.3 g of H2 = 15.3 / 2.0159 = 7.59 moles

7.59 moles of H2 will require 7.59 /3 = 2.53 moles of N2

So N2 is the limiting reagent.

Number of moles of NH3 formed = 2 x 1.25 = 2.5 moles

Amount in grams = 17.01 x 2.5

= 42.55 g NH3

Number of moles of H2 utilised = 1.25 x3 = 3.75 moles

Mass = 3.75 x 2.0159 = 7.55 g

Amount of H2 left after the reaction is complete :

= 15.3 - 7.55

= 7.75 g hydrogen

.

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