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Solutions from the graph Neytex (10) passing through point = (4,4) het Equation or parabola. fala 12 fbx & C Standard form of parabola with vertex (ha) Para a (x-hg tk cilven vertex (hak) = (1,0) 80, fala q (x-132 to flag acarige as it paying thob (9,-4) je apa yn - 4 ond 1=4 $0, foi o 9 (-10 "Aca (4.12 - 4 - axa
so equation of required parabola. far = a (x4.22 (putting in @) fev -409-132 (3241-94) 17 – 4 x 2 of 8x - 4 of A
.
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