## Answers

1)

P^{H} = - log [H^{+}]

given P^{H} = 7.4 there fore

[H^{+}] = 10^{-PH} = 10^{-(7.4)} = **3.98x10 ^{-8}**

[H^{+}] = **3.98x10 ^{-8}**

2)

P^{OH} = 14 - P^{H}

P^{OH} = 14 - 7.4 = 6.6

P^{OH} = - log [OH^{-}]

[OH^{-}] = 10^{-POH} = 10^{-(7.4)} = **2.51 x 10 ^{-7}**

[OH^{-}] = **2.51 x 10 ^{-7}**

3)

In the scale of PH 0 to 14

PH is 7 is nuetral

less than 7 it is acid

more than 7 it is basic

**so give PH is 7.4 so that is basic (alkaline)**

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