## Answers

q R, = 8. cox 10²2 = 0.8ooke R2= 2.40x1032=2.40kn R3 = 5.00 kr When R, R2 & R3 are in series then reststance Rnet =R,+R2 + R3 Ronet = (0.800 +2.40 +5:00) ke Rnet 8.20 kr Ang when R, R2 6R3 are in parallel then if net resistance is Reg, then 1 2 + 1 2 + 1 2 3 Req R + ochro + so I 2.40 0.8. = 75+ 5 +2.4 12 22.4 Reg 12 : Reg 12 22.4 = 0.536k2 Reg Any

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