1 answer

1. (1 point) Select a conductor from the ACSR table capable of carrying 750 Amps of current at 75% load.

Question:

1. (1 point) Select a conductor from the ACSR table capable of carrying 750 Amps of current at 75% load.

2. (2 point) Verify the cross-sectional area of ACSR Martin expressed in circular mils of aluminum. Determine the equivalent cross-sectional area in square meters.

Characteristics of aluminum cable, steel, reinforced (Aluminum Company of America)- ACSR 07 07 07 07 TABLE A.4 08 Aluminum 08

Characteristics of aluminum cable, steel, reinforced (Aluminum Company of America)- ACSR 07 07 07 07 TABLE A.4 08 Aluminum 08 1781 000 84 4 01456 19 00874 oa 08 08 08 900 000 50 400 9699 00493 1 300 00052 0 0653 00655 00656 0718 00729 00749 00760 850 000 47000 9 160 00479 1 250 00691 0,0692 00694 00695 00761 00771 00792 00803 Ca Pla nep co per ft-600000 1351 00O 543015829 009491 000000 750000 43 100 8082 จ0450 1 1 60 00783 00784 00786 100788 100862 00872 100894 00906 000000 650000 37 100 7019 00420 106000903009050090700909 0099401005 10250 1035 0098 2101078| 0.1088|01118|01 12B. 000000 Caidinai -954,00 154-11-10 1329 7| 01329 | 1196 | 000000| 34200| 6 000 00979 00000 000000 000000 000000 0C0000 00980| 00981 60 0390 00000 00403 ︶ 0 0 0 0 000000 000000 000000 000000 00000 00000 101Ω 009988 970 0 104 0104 0104 0104 0 1145 01155 0 1175 01185 950 0 107 0 107 107 0108 01 1 78 01 1 88 | O 1218 | 0 1 228 900 0117 0118 10118 0119 01288 | 01308 | 0 1358101378 776. 6 5 5 0401 564554 795 00054301214 7 01214 1093 4.5 4 4 4 79500026 01749 701360 108 795000302 01628 19 00977 1 140 3323 900 0117 0117 0117 0117 01288 | 01288 101288 101288 910 0117 0117 0117 0117 01288 | 01288 |01288 |01288 B30 0 131 0 131 01 31 0 132 0 1442 0 1452 | 01472) 0 1482 0407 840 0 131 0131 0131 0131 01442 01442 01442 0,1442 840 0131 0131 0131 0131 01442 01442 014420.1442 0399 800 0140 0140 0141 0141 01541 01571101591101601 22221 45000028 1005193 00355 000 000 000 000 000 000 419000 24500 4527 00337 000 000 000 000 000 000 770 014/ 0147 148 0148 01618101638 01678 01688 780 0147 0 147 0147 0171618 01618 01618 C1618 780 0147 0147 0 147 0147 01618 01618 01618 01618 750 0154 0155 0155 0155 01695 01715 0.1755101775 60 0154 0154 0154 0154 0 1700 01720 0 1720 01720 730 0 168 0 168 0 168 0 188 01 849 01 659 0.1859 01 859 000 000 000 000 000 000 0414 000 000 000 500 500 000 Grosbeak 636 000 26 201564 7 0.1216 0990 000 000 000 000 000 38050024100 439 00327 444 333333 33廴333 223223 322322 22222 22222 730 0168 0 168 0168 0 168 0 1849 0 1859 0 1859 0 1859 670 0 196 0 196 0 196 0 196 0 216 670 0 196 0 196 0196 0196 0216 400 400 000 000 800 mm 讚300 300 66 25000016190 2885 00265 000 000 000 000 000 um 5 3 6 56 81 188 700 12650 2178 00230 000 300 000 000 000 500 $50 5 3 3 2 9 tFor conductor at 75'C au at 25'C wind 1 4 miles per hour (2 ft/sec) frequency -60Hz r Current App。к 75% Capacity s 75% o11he Appros Current Car r ng Capacity in Amps and s aooonmately the current which wa poduce so c conductor terno 000 500 000 000 500 000 3 33鬻49 in 25 C air terme. 000 000 500 500 500 600 195 195 15 15 15繃 2 000 000 000 000 000 500 36 36 36 006 005 sso tae) 500 000 000 500 500 ; 47 39 39 nd i 4 m les per hour

Answers

As per the ion chavadtorshes L) Given cu双ont 1.1so Amb at 75% we need to choose cablo accodiną lo abng at full leod ACSR Here

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