0% Нас он CH3 CH3 H20 Br however, does not result from the addition of HO-Br, for example. Instea...

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0% &#1053;&#1072;&#1089; &#1086;&#1085; CH3 CH3 H20 Br however, does not result from the addition of HO-Br, for example. Instead the addition is done indirectly by reaction of the alkene with Br2 in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as a bromonium ion. In the second step of the reaction, water is the nucleophile and reacts with the bromonium ion to yield the product The reaction can also proceed using an alcohol as the solvent instead of water, to give a 1,2-haloether Draw curved arrows to show the movement of electrons in this step of the mechanism An CH3 CH3 Br CH3 CH3 H3C Br Br. :Br. Draw s al formulas for all alkenes that could be used to prepare the alcohol shown below by H3C OH 2. NaBH4 CH3 You do not have to consider stereochemistry Include only alkenes that will give the alcohol as the single major product. Separate structures with signs from the drop-down menu. . . &#1086;&#1085; 1. Hg(OAch, H20 CH3 H3C c Ht adds to the sp? carbon with the most hydrogens to yield the most stable carbocation to an alkene yields an rearrangements can occur prior to the addition of watet. intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is To avoid the possibility of rearangement and still give a Markovn&#305;kov alcohol, alkenes can instead be treated with m acetate in aqueous THF and then subsequently reduced with sodium through a cyclic mercurinium ion irnt hich cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to borohydride. This reaction alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved atrows to show the movement of electrons in this step of the m OAc OAc Hg Hg H2C &#1114;&#1077; H2C CH3 CH3 PreviousN Draw a for the formed upon hydrob ation of the alkene below CH3 CH3CHCH= CH2 . Use wedge and hash bonds ONLY for rings. . Do not show stereochemistry in other cases. . If the reaction s a racemic mixture, just draw one stereoisomer CH3 CH3 1. BH3-THF 2. NaOH, H20, H2o2 &#1086;&#1085; CH2 H3C Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regsochemistry The boron atom is an electrophile and thus follows Markovnikov's rule in adding to the carbon alcohol Draw curved arrows to show the movement of electrons in this step of the mechanism An CH3 CH3 H H-BH2 BH CH2 H3C 10 iterm attempts remaining select the s that could be used to carry out the on, giving the al as the single major In each case trans The procedures are Hydroborationoxidation alkene + &#1042;&#1053;&#1047;; then H2O2, OH. Oxymercuration: alkene + Hg(OAc)2, H20; then NaBH4 CH3 CH3 CH3 CH3CHCH CCH3CHCHCHCH3 CH3 CH3 &#1086;&#1085; &#1086;&#1085; CH3CH2 CH2CH3 CH2CH2CHCH2CH2CH3 Iry Another Version 10 item attempts remaining Either the reactant (X) or the major o product is missing from the below Draw the missing 1S XH2Pd/C CH2CH(CH3)2 . You do not have to consider stereochemistry . In the case of a missing reactant, there may be more than one answer. If so, draw all possible reactants, . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple reactants using the +sign from the drop-down menu.  0% &#1053;&#1072;&#1089; &#1086;&#1085; CH3 CH3 H20 Br however, does not result from the addition of HO-Br, for example. Instead the addition is done indirectly by reaction of the alkene with Br2 in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as a bromonium ion. In the second step of the reaction, water is the nucleophile and reacts with the bromonium ion to yield the product The reaction can also proceed using an alcohol as the solvent instead of water, to give a 1,2-haloether Draw curved arrows to show the movement of electrons in this step of the mechanism An CH3 CH3 Br CH3 CH3 H3C Br Br. :Br.  Draw s al formulas for all alkenes that could be used to prepare the alcohol shown below by H3C OH 2. NaBH4 CH3 You do not have to consider stereochemistry Include only alkenes that will give the alcohol as the single major product. Separate structures with signs from the drop-down menu. . .  &#1086;&#1085; 1. Hg(OAch, H20 CH3 H3C c Ht adds to the sp? carbon with the most hydrogens to yield the most stable carbocation to an alkene yields an rearrangements can occur prior to the addition of watet. intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is To avoid the possibility of rearangement and still give a Markovn&#305;kov alcohol, alkenes can instead be treated with m acetate in aqueous THF and then subsequently reduced with sodium through a cyclic mercurinium ion irnt hich cannot rearrange. Water adds to the cyclic intermediate at the most substituted carbon to borohydride. This reaction alcohol. The reduction step with sodium borohydride is complex and involves radicals. Draw curved atrows to show the movement of electrons in this step of the m OAc OAc Hg Hg H2C &#1114;&#1077; H2C CH3 CH3 PreviousN  Draw a for the formed upon hydrob ation of the alkene below CH3 CH3CHCH= CH2 . Use wedge and hash bonds ONLY for rings. . Do not show stereochemistry in other cases. . If the reaction s a racemic mixture, just draw one stereoisomer  CH3 CH3 1. BH3-THF 2. NaOH, H20, H2o2 &#1086;&#1085; CH2 H3C Alkenes can be hydrated via the addition of borane to yield alcohols with non-Markovnikov regsochemistry The boron atom is an electrophile and thus follows Markovnikov's rule in adding to the carbon alcohol Draw curved arrows to show the movement of electrons in this step of the mechanism An CH3 CH3 H H-BH2 BH CH2 H3C 10 iterm attempts remaining  select the s that could be used to carry out the on, giving the al as the single major In each case trans The procedures are Hydroborationoxidation alkene + &#1042;&#1053;&#1047;; then H2O2, OH. Oxymercuration: alkene + Hg(OAc)2, H20; then NaBH4 CH3 CH3 CH3 CH3CHCH CCH3CHCHCHCH3 CH3 CH3 &#1086;&#1085; &#1086;&#1085; CH3CH2 CH2CH3 CH2CH2CHCH2CH2CH3 Iry Another Version 10 item attempts remaining  Either the reactant (X) or the major o product is missing from the below Draw the missing 1S XH2Pd/C CH2CH(CH3)2 . You do not have to consider stereochemistry . In the case of a missing reactant, there may be more than one answer. If so, draw all possible reactants, . Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple reactants using the +sign from the drop-down menu.

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We were unable to transcribe this imageE t OAC OAC DAL H, C h, C Ac. CH CH3 (H&#12524; yeaut m Same way as bush- and jormation oga CH3 SJT or udatisn hy CH &#12371; &#12510; OH ctu .

0% Нас он CH3 CH3 H20 Br however, does not result from the addition of HO-Br, for example. Instea...

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